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fix add slef base url openai error (#1854)

### What problem does this PR solve?

### Type of change

- [x] Bug Fix (non-breaking change which fixes an issue)
tags/v0.10.0
Kevin Hu 1 year ago
parent
commit
1d5a9b74ff
No account linked to committer's email address
2 changed files with 3 additions and 3 deletions
  1. 2
    2
      api/apps/llm_app.py
  2. 1
    1
      graphrag/index.py

+ 2
- 2
api/apps/llm_app.py View File

req["api_key"], llm.llm_name, base_url=req.get("base_url")) req["api_key"], llm.llm_name, base_url=req.get("base_url"))
try: try:
arr, tc = mdl.encode(["Test if the api key is available"]) arr, tc = mdl.encode(["Test if the api key is available"])
if len(arr[0]) == 0 or tc == 0:
if len(arr[0]) == 0:
raise Exception("Fail") raise Exception("Fail")
embd_passed = True embd_passed = True
except Exception as e: except Exception as e:
try: try:
m, tc = mdl.chat(None, [{"role": "user", "content": "Hello! How are you doing!"}], m, tc = mdl.chat(None, [{"role": "user", "content": "Hello! How are you doing!"}],
{"temperature": 0.9,'max_tokens':50}) {"temperature": 0.9,'max_tokens':50})
if not tc:
if m.find("**ERROR**") >=0:
raise Exception(m) raise Exception(m)
except Exception as e: except Exception as e:
msg += f"\nFail to access model({llm.llm_name}) using this api key." + str( msg += f"\nFail to access model({llm.llm_name}) using this api key." + str(

+ 1
- 1
graphrag/index.py View File

obj = [obj] obj = [obj]
if isinstance(obj, list): if isinstance(obj, list):
for i in obj: keyset.add(i) for i in obj: keyset.add(i)
return [{"id": i, "children":[]} for i in obj]
return [{"id": re.sub(r"\*+", "", i), "children":[]} for i in obj]
arr = [] arr = []
for k,v in obj.items(): for k,v in obj.items():
k = re.sub(r"\*+", "", k) k = re.sub(r"\*+", "", k)

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